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=6Y^2-48Y
We move all terms to the left:
-(6Y^2-48Y)=0
We get rid of parentheses
-6Y^2+48Y=0
a = -6; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·(-6)·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*-6}=\frac{-96}{-12} =+8 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*-6}=\frac{0}{-12} =0 $
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